\(\frac{x-1}{x-2}+\frac{x+3}{x-4}=\frac{2}{\left(x-2\right)\left(x-4\right)}\)
\(ĐKXĐ:x\ne2,x\ne4\)
\(MC:\left(x-2\right)\left(x-4\right)\)
\(PT\Leftrightarrow\left(x-1\right)\left(x-4\right)+\left(x+3\right)\left(x-2\right)=2\)
\(\Leftrightarrow x^2-5x+4+x^2+x-6=2\)
\(\Leftrightarrow2x^2-4x-4=0\)
\(\Leftrightarrow2\left(x^2-2x-2\right)=0\)
\(\Leftrightarrow x^2-2x=2\)
\(\Leftrightarrow x\left(x-2\right)=2\)
\(\Leftrightarrow x\left(x-2\right)-2=0\)
Vậy giờ mình kết luận x=? hả bạn? Mình dở toán lắm. (T-T)