Question

Giúp mình bài này nhé

Answer 1

`1/8 - 2x^2 = 0`

`2x^2 = 1/8 - 0`

`2x^2 = 1/8`

`<=> x = -1/4; 1/4`

Vậy `x = {-1/4; 1/4}`

Answer 2

=> 2x² = \(\dfrac{1}{8}\)

=> x² = \(\dfrac{1}{16}\)

=> x = \(\sqrt[]{\dfrac{1}{16}}\)=> x = \(\dfrac{1}{4}\) hoặc \(\dfrac{-1}{4}\)