Bài 3:
1:
a: =>\(15x-10-20+12x=1\)
=>27x=31
=>x=31/27
b: \(\Leftrightarrow\left|x+1\right|=2x+12\)
=>\(\left\{{}\begin{matrix}x>=-6\\\left(2x+12-x-1\right)\left(2x+12+x+1\right)=0\end{matrix}\right.\)
=>\(\left\{{}\begin{matrix}x>=-6\\\left(x+11\right)\left(3x+13\right)=0\end{matrix}\right.\Leftrightarrow x\in\left\{-\dfrac{13}{3}\right\}\)
2:
\(\Leftrightarrow2x-6-6x+3>12\)
=>-4x>12+6-3=15
=>x<-15/4
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