Question

giúp mik nhé mọi người ơi

 

Answer 1

\(\Leftrightarrow\left|x-\dfrac{3}{4}\right|=\dfrac{17}{2}+\dfrac{7}{4}=\dfrac{41}{4}\)

\(\Leftrightarrow x-\dfrac{3}{4}\in\left\{\dfrac{41}{4};-\dfrac{41}{4}\right\}\)

hay \(x\in\left\{11;-\dfrac{19}{2}\right\}\)

Answer 2

\(\left|x-\dfrac{3}{4}\right|=\dfrac{41}{4}\)

TH1 : \(x-\dfrac{3}{4}=\dfrac{41}{4}\Leftrightarrow x=\dfrac{44}{4}=11\)

TH2 : \(x-\dfrac{3}{4}=-\dfrac{41}{4}\Leftrightarrow x=-\dfrac{38}{4}=-\dfrac{19}{2}\)

Answer 3

TH1 x-3/4>0=>x=11
TH2 x-3/4<0=>x=-9,5 nhé

Answer 4

\(\dfrac{17}{2}- \left|x-\dfrac{3}{4}\right|=\dfrac{-7}{4}\)

<=>\(\left|x-\dfrac{3}{4}\right|=\dfrac{17}{2}-\dfrac{-7}{4}\)

<=>\(\left|x-\dfrac{3}{4}\right|=\dfrac{34}{4}+\dfrac{7}{4}\)

<=>\(\left|x-\dfrac{3}{4}\right|=\dfrac{41}{4}\)

<=>\(\left[{}\begin{matrix}x-\dfrac{3}{4}=\dfrac{41}{4}\\x-\dfrac{3}{4}=\dfrac{-41}{4}\end{matrix}\right.\)

<=>\(\left[{}\begin{matrix}x=11\\x=\dfrac{-19}{2}\end{matrix}\right.\)