\(n_{NaOH}=0,1.0,15=0,03\left(mol\right)\)
PTHH: CH3COOH + NaOH ---> CH3COONa + H2O
0,03<----------0,03
\(\Rightarrow C_{M\left(CH_3COOH\right)}=\dfrac{0,03}{0,1}=0,3M\\ \Rightarrow B\)
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