Question

giúp mik giải vs ạ

Answer 1

Đặt \(g\left(x\right)=2x-3=0\Leftrightarrow x=\dfrac{3}{2}\)

\(h\left(x\right)=4-5x=0\Leftrightarrow x=\dfrac{4}{5}\)

\(f\left(x\right)=x^2-16=0\Leftrightarrow\left[{}\begin{matrix}x=4\\x=-4\end{matrix}\right.\)

\(k\left(x\right)=\left(x+1\right)\left(x-3\right)=0\Leftrightarrow\left[{}\begin{matrix}x+1=0\\x-3=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-1\\x=3\end{matrix}\right.\)