Bài 4:
a: \(\widehat{BAx}=180^0-70^0=110^0\)
a)Ta có: \(\widehat{aMb}\) +\(\widehat{EMN}\)=180( 2 góc kề bù)⇔\(\widehat{aMb}\)=180-\(\widehat{EMN}\)=180-120=60
Mà \(\widehat{aMb}\)=\(\widehat{MN}F\)=60( 2 góc SLT) =>a//b
b)Vì a//b nên \(\widehat{x}\)=\(\widehat{NFE}\)=90 (2 góc SLT )