Question

giúp mih vs ạ :(( e cần gấp

Answer 1

\(x+y+z=0\rArr\left(x+y+z\right)^2=0\)

\(\Rightarrow x^2+y^2+z^2+2xy+2yz+2zx=0\)

\(\rArr x^2+y^2+z^2+2\left(xy+yz+xz\right)=0\)

\(\rArr x^2+y^2+z^2=0\) (do \(xy+yz+xz=0\) )

\(\rArr x=y=z=0\)

Do đó:

\(\left(x-1\right)^{2023}+y^{2024}+\left(z+1\right)^{2025}=\left(0-1\right)^{2023}+0^{2024}+\left(0+1\right)^{2025}=-1+0+1=0\)