Question

giúp em vs mn ơi

Answer 1

\(a,=x^2\left(x^2+2x+1\right)=x^2\left(x+1\right)^2\\ b,=\left(x-y\right)^2-25=\left(x-y-5\right)\left(x-y+5\right)\\ c,=7\left(x^2-2x+1\right)=7\left(x-1\right)^2\\ d,=\left(x+2\right)^2-y^2=\left(x+y+2\right)\left(x-y+2\right)\\ e,=x\left(x^2-2x+1\right)=x\left(x-1\right)^2\\ f,=\left(x+y\right)^2-9=\left(x+y+3\right)\left(x+y-3\right)\\ g,=y\left(x^2-2x+1\right)=y\left(x-1\right)^2\\ h,=\left(x-3\right)^2-y^2=\left(x-y-3\right)\left(x+y-3\right)\\ k,=\left(x-y\right)^2-z^2=\left(x-y-z\right)\left(x-y+z\right)\\ m,=5\left(x-y\right)+a\left(x-y\right)=\left(a+5\right)\left(x-y\right)\)