Question

giúp em vs ạ 

Answer 1

\(a,=x^3+1-x^3+1=2\\ b,Sửa:\dfrac{x^3+1}{3x^2+6x+3}=\dfrac{\left(x+1\right)\left(x^2-x+1\right)}{3\left(x+1\right)^2}=\dfrac{x^2-x+1}{3\left(x+1\right)}\)