\(=\dfrac{3}{x}\cdot\left(-x\right)-\dfrac{3}{x}\cdot\dfrac{3}{3-x}=-3+\dfrac{9}{x\left(x-3\right)}\)
\(=\dfrac{-3x\left(x-3\right)+9}{x\left(x-3\right)}=\dfrac{-3x^2+9x+9}{x\left(x-3\right)}\)
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