\(M_{FeO}=56+16=72\left(đvc\right)\)
\(M_{Fe_2O_3}=56\cdot2+16\cdot3=160\left(đvc\right)\)
\(M_{Cu\left(NO_3\right)_2}=64+\left(14+48\right)\cdot2=188\left(đvc\right)\)
\(M_{NaCl}=23+35.5=58.5\left(đvc\right)\)
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