\(\left(\dfrac{x}{2}-\dfrac{3}{2}\right)\cdot\left(3x-\dfrac{1}{5}\right)=0\)
\(\Rightarrow\) \(\left(\dfrac{x}{2}-\dfrac{3}{2}\right)\) Hoặc \(\left(3x-\dfrac{1}{5}\right)\) = 0
+) \(\dfrac{x}{2}-\dfrac{3}{2}=0\)
\(\Rightarrow\) \(\dfrac{x}{2}=0+\dfrac{3}{2}\)
\(\Rightarrow\) \(\dfrac{x}{2}=\dfrac{3}{2}\)
\(\Rightarrow\) \(x=3\)
+) \(3x-\dfrac{1}{5}=0\)
\(\Rightarrow\) \(3x=\dfrac{1}{5}\)
\(\Rightarrow\) \(x=\dfrac{1}{5}\div3\)
\(\Rightarrow\) \(x=\dfrac{1}{5}\cdot\dfrac{1}{3}=\dfrac{1}{15}\)
\(\Rightarrow\) \(x\) \(\in\) {\(3;\dfrac{1}{15}\)}
Vậy chọn B
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