a, \(CH_2=CH-CH=CH_2+Br_2\xrightarrow[1:1]{-80^oC}CH_2Br-CHBr-CH=CH_2\)
\(CH_2=CH-CH=CH_2+Br_2\xrightarrow[1:1]{40^oC}CH_2Br-CH=CH-CH_2Br\)
b, \(CH\equiv C-CH_3+H_2\xrightarrow[Pd/PbCO_3]{t^o}CH_2=CH-CH_3\)
c, \(3C_2H_2\xrightarrow[xt]{t^o,p}C_6H_6\)
d, \(CH\equiv CH+HCl\underrightarrow{HgCl_2}CH_2=CHCl\)
Bạn tham khảo nhé!