a) \(t_2=\dfrac{S_2}{v_2}=\dfrac{20}{40}=\dfrac{1}{2}\left(h\right)\)
b) \(1h30ph=\dfrac{3}{2}h\)
\(v_{tb}=\dfrac{S_1+S_2}{t_1+t_2}=\dfrac{100+20}{\dfrac{3}{2}+\dfrac{1}{2}}=60\left(\dfrac{km}{h}\right)\)
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