Question

Giúp em với ạ, cản ơn ạ 💕

Answer 1

d: \(\Leftrightarrow\left(x+2\right)^2-\left(x-2\right)^2=8\)

\(\Leftrightarrow x^2+4x+4-x^2+4x-4=8\)

=>8x=8

hay x=1(nhận)

Answer 2

`(x+2)/(x-2)-(x-2)/(x+2)=8/(x^2-4)(x\ne+-2)`

`<=>(x+2)^2/((x-2)(x+2))-(x-2)^2/((x-2)(x+2))-8/((x-2)(x+2))=0`

`<=>(x^2+4x+4-x^2+4x-4-8)/((x-2)(x+2))=0`

`<=>(8x-8)/((x-2)(x+2))=0`

`=>8x-8=0<=>x=1`

Vậy `S={1}`