\(b,=\left[\dfrac{\sqrt{5}\left(\sqrt{5}+1\right)}{\sqrt{5}+1}+2\right]\left[\dfrac{\sqrt{5}\left(\sqrt{5}-1\right)}{\sqrt{5}-1}-2\right]\\ =\left(\sqrt{5}+2\right)\left(\sqrt{5}-2\right)=5-4=1\\ c,=\dfrac{\sqrt{14}\left(\sqrt{7}+\sqrt{2}\right)}{\sqrt{14}}-\dfrac{5\left(\sqrt{7}-\sqrt{2}\right)}{5}\\ =\sqrt{7}+\sqrt{2}-\sqrt{7}+\sqrt{2}=2\sqrt{2}\)