Cho tử số của nó là \(x\)
Mẫu số của phân số đó là: \(x+5\)
Phân số đó có dạng: \(\dfrac{x}{x+5}\)
Mà giá trị của phân số này bằng \(\dfrac{6}{7}\) nên:
\(\dfrac{x}{x+5}=\dfrac{6}{7}\)
\(7\times x=6\times\left(x+5\right)\)
\(7\times x=6\times x+6\times5\)
\(7\times x-6\times x=30\)
\(x=30\)
Vậy tử số ban đầu là 30
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