\(\frac{3-2x}{5}=\frac{-2x+1}{3}\)
=> 5.(-2x+1) = 3.(3-2x)
=> -10x + 5 = 9 - 6x
=> -4x + 5 = 9
=> -4x = 4
=> x = -1
\(\frac{x-1}{x-5}=\frac{6}{7}\)
=> 7.(x-1) = 6.(x-5)
=> 7x-7 = 6x-30
=> 7 = x - 30
=> x = 37
1, => 3( 3 - 2x ) = 5( -2x + 1 )
=> 9 - 6x = -10x + 5
=> ( 9 - 6x ) - ( -10x + 5 ) = 0
=> 9 - 6x + 10x - 5 = 0
=> ( 9 - 5 ) + ( 6x - 10x ) = 0
=> 4 + x( 6 - 10 ) = 0
4 + -4x = 0
=> x = 1
hihih chắc z ^^