B5:
\(n_{CuSO_4}=0,2.0,1=0,02\left(mol\right)\\ CuSO_4+2NaOH\rightarrow Cu\left(OH\right)_2+Na_2SO_4\\ Cu\left(OH\right)_2\rightarrow\left(t^o\right)CuO+H_2O\\ n_{CuO}=n_{Cu\left(OH\right)_2}=n_{Na_2SO_4}=n_{CuSO_4}=0,02\left(mol\right)\\ m_D=m_{CuO}=0,02.80=1,6\left(g\right)\\ m_{Na_2SO_4}=142.0,02=2,84\left(g\right)\)