Question

Giúp ạ

Answer 1

a) \(n_{O_2}=\dfrac{12,8}{32}=0,4\left(mol\right)\)

PTHH: 2H₂O --đp--> 2H₂ + O₂

_____0,8<---------0,8<---0,4

=> m_H2O = 0,8.18 = 14,4 (g)

b) V_H2 = 0,8.22,4 = 17,92(l)

Answer 2

a,nO²=m/M=12,8/16=0,8

Theo pthh

nH²O=nO²=0,8 mol

mH²O=n×M=0,8×(16+2)=14,4

b,

V H²O=n×22,4=0,8×22,4=17,92(l)