Question

giải Þhương trình sau
       x + 1 /2016  +  x+3 /2014 = x+5 /2012  +  x+7 /2010

Answer 1

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\(\frac{x+1}{2016}+\frac{x+3}{2014}=\frac{x+5}{2012}+\frac{x+7}{2010}\)

\(\frac{x+1}{2016}+1+\frac{x+3}{2014}+1=\frac{x+5}{2012}+1+\frac{x+7}{2010}+1\)

\(\frac{x+2017}{2016}+\frac{x+2017}{2015}=\frac{x+2017}{2012}+\frac{x+2017}{2010}\)

\(\Leftrightarrow\left(x+2017\right)\left(\frac{1}{2016}+\frac{1}{2015}-\frac{1}{2012}-\frac{1}{2010}\right)=0\)

MÀ \(\left(\frac{1}{2016}+\frac{1}{2015}-\frac{1}{2012}-\frac{1}{2010}\right)\ne0\)
=> x + 2017 = 0

<=> x = -2017