google chưa tính phí mà ! :v
\(\frac{x+1}{2016}+\frac{x+3}{2014}=\frac{x+5}{2012}+\frac{x+7}{2010}\)
\(\frac{x+1}{2016}+1+\frac{x+3}{2014}+1=\frac{x+5}{2012}+1+\frac{x+7}{2010}+1\)
\(\frac{x+2017}{2016}+\frac{x+2017}{2015}=\frac{x+2017}{2012}+\frac{x+2017}{2010}\)
\(\Leftrightarrow\left(x+2017\right)\left(\frac{1}{2016}+\frac{1}{2015}-\frac{1}{2012}-\frac{1}{2010}\right)=0\)
MÀ \(\left(\frac{1}{2016}+\frac{1}{2015}-\frac{1}{2012}-\frac{1}{2010}\right)\ne0\)
=> x + 2017 = 0
<=> x = -2017