\(\Leftrightarrow\orbr{\begin{cases}x^2+6x+6=0\\\frac{\left(x+3\right)^2}{\left(x+4\right)^2}=0\end{cases}}\)
\(\text{+)(x+3)^2/(x+4)^2=0 suy ra (x+3)^2=0 suy ra: x+3=0 suy ra: x=-3}\)
\(+,x^2+6x+6=0\Rightarrow\left(x^2+6x+9\right)=3\Rightarrow\left(x+3\right)^2=3\)
\(\Leftrightarrow x+3=\pm\sqrt{3}\Leftrightarrow x=-\sqrt{3}-3.hoặc:x=\sqrt{3}-3\)
Vậy,,,,,,,,,,
1)giải pt \(x^3-9x^2+6x-6-3\sqrt[3]{6x^2+2}=0\)
2) giải hệ pt \(\int^{\sqrt{x}\left(1+\frac{3}{x+3y}\right)=2}_{\sqrt{7y}\left(1-\frac{3}{x+3y}\right)=4\sqrt{2}}\)
Giai PT:
\(x^2+6x+6+\left(\frac{x+3}{x+4}\right)^2=0\)
giải pt \(\frac{4}{\left(\sqrt{x-1}-\sqrt{x-3}\right)^2}+x^2-6x+4=0\)
2. Giải PT:
a) \(\frac{9x-7}{\sqrt{7x+5}}=\sqrt{7x+5}.\)
b) \(\sqrt{4x-20}+3\sqrt{\frac{x-5}{9}}-\frac{1}{3}\sqrt{9x-45}=4.\)
c) \(2x-x^2+\sqrt{6x^2-12x+7}=0.\)
d) \(\left(x+1\right)\left(x+4\right)-3\sqrt{x^2+5x+2}=6.\)
GIẢI PT \(3\left(\frac{x+3}{x-2}\right)^2+168\left(\frac{x-3}{x+2}\right)^2-46\frac{x^2-9}{x^2-4}=0\)
giải bất pt
\(\frac{\sqrt{x^2-x-6}+3\sqrt{x}-\sqrt{2\left(x^2+5x+3\right)}}{x+3-\sqrt{2\left(x^2+10\right)}}< =0\)
(1) giải pt quy về \(ax^2+bx+c=0\)
1) \(x^2=3x\) 2) \(x^2-3x=4\)
3) \(x^4-5x^2+6=0\) 4) \(x^3=9x\)
5) \(\left(x+2\right)\left(x-3\right)=x^2-4\) 6) \(\dfrac{x+11}{x^2-1}-\dfrac{x-1}{x+1}=\dfrac{2\left(x+7\right)}{x+1}\)
giúp mk vs mk cần gấp
Giải pt: \(\left(\frac{x+2}{x+1}\right)^2+\left(\frac{x-2}{x-1}\right)^2-\frac{5x^2-4}{2x^2-1}=0\)
1, Giải pt
\(x^4-8x^3+21x^2-24x+9=0\)
2, Giải pt
\(\left(x+4\right)\left(x+6\right)\left(x-2\right)\left(x-12\right)=25x^2\)
Giải giúp mk vs ạ. Cảm ơn m.n nhìu
