\(\left(\dfrac{3x-40}{50}\right)+\left(\dfrac{3x-10}{40}\right)+\dfrac{x+30}{20}+\dfrac{x-90}{10}=0\)
=>\(\left(\dfrac{3x-40}{50}-1\right)+\left(\dfrac{3x-10}{40}-2\right)+\dfrac{x+30}{20}-3+\dfrac{x-90}{10}=0\)
=>\(\dfrac{3x-90}{50}+\dfrac{3x-90}{40}+\dfrac{x-90}{10}+\dfrac{x-30}{20}=0\)
=>\(\dfrac{-x+90}{10}=\left(x-30\right)\left(\dfrac{3}{50}+\dfrac{3}{40}+\dfrac{1}{20}\right)\)
=>\(\dfrac{-x+90}{10}=\left(x-30\right)\cdot\dfrac{37}{200}\)
=>\(-x+90=\dfrac{37}{20}\left(x-30\right)\)
=>\(\dfrac{37}{20}x-555=-x+90\)
=>\(\dfrac{57}{20}x=90+555=645\)
=>\(x=645:\dfrac{57}{20}=\dfrac{4300}{19}\)
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