`#3107.101107`
`b)`
\(\dfrac{2\left(3x+1\right)+1}{4}-5=\dfrac{2\left(3x-1\right)}{5}-\dfrac{3x+2}{10}\)
`<=>`\(\dfrac{5\left[2\left(3x+1\right)+1\right]-100}{20}=\dfrac{4\left[2\left(3x-1\right)\right]-2\left(3x+2\right)}{20}\)
`<=>`\(5\left(6x+2+1\right)-100=4\left(6x-2\right)-\left(6x+4\right)\)
`<=> 5(6x + 3) - 100 = 24x - 8 - 6x - 4`
`<=> 30x + 15 - 100 = 18x - 14`
`<=> 30x - 18x = 100 - 15 - 14`
`<=> 12x = 81`
`<=> x = 81/12 = 27/4`
Vậy, `x = 27/4.`
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