Question

Giải pt:  \(x^2+\left(\frac{1}{x+1}\right)^2=1\)

Answer 1

\(\Leftrightarrow x^2\left(x+1\right)^2+1=\left(x+1\right)^2\Leftrightarrow x^4+2x^3-2x=0\)

\(\Leftrightarrow x\left(x^3+2x^2-2\right)=0\)

\(\Leftrightarrow x=0\text{ or }x=\frac{1}{81}\left(\sqrt[3]{373997-59049\sqrt{33}}+27\sqrt[3]{19+3\sqrt{33}}\right)-\frac{2}{3}\)

 

Answer 2

Nhìn cái nghiệm lẻ thế kia chắc là đề sai