Question

Giai pt:

x-241/17+x-220/19+x-195/21+x-161/23=10

Answer 1

\(\dfrac{x-241}{17}+\dfrac{x-220}{19}+\dfrac{x-195}{21}+\dfrac{x-161}{23}=10\)

<=>\(\dfrac{x-241}{17}-1+\dfrac{x-220}{19}-2+\dfrac{x-195}{21}-3\dfrac{x-161}{23}-4=0\)

<=>\(\dfrac{x-258}{17}+\dfrac{x-258}{19}+\dfrac{x-158}{21}+\dfrac{x-158}{23}=0\)

<=>\(\left(x-258\right)\left(\dfrac{1}{17}+\dfrac{1}{19}+\dfrac{1}{21}+\dfrac{1}{23}\right)=0\)

vì 1/17+1/19+1/21+1/23 khcas 0

=>x-258=0<=>x=258

vậy...............

chcus bạn học tốt ^^