Question

Giải pt:

​\(\sqrt{3x^2}\)= x+2\(\sqrt{x^2+6x+9}\)= 3x-6\(\sqrt{x^2-4x+4}\)-2x+5=0

Answer 1

3xbình =(x+2) bình => 3x bình = x bìn+ 4 x +4 ^=> 2x bình - 4x -4 =0 => 2. (x bình - 2x -1)=0

Answer 2

2. \(\sqrt{x^2+6x+9}=3x-6\)

\(\sqrt{\left(x-3\right)^2}=3x-6\)

\(x-3=3x-6\)

\(x-3-3x+6=0\)

\(-2x+9=0\)

\(-2x=-9\)

\(x=\frac{9}{2}\)

3. \(\sqrt{x^2-4x+4}-2x+5=0\)

\(\sqrt{\left(x-2\right)^2}-2x+5=0\)

\(x-2-2x+5=0\)

\(-x+3=0\)

\(x=3\)