Đk : x >= -70
Đặt : \(\sqrt{x+70}=a\); \(\sqrt{2x^2+4x+16}=b\)
=> 6x^2+10x-92 = 3b^2 - 2a^2
pt trở thành :
3b^2 - 2a^2 + ab = 0
<=> (3b^2+3ab)-(2ab+2a^2) = 0
<=> (a+b).(3b-2a) = 0
<=> a+b=0 hoặc 3b-2a = 0
<=> a=-b hoặc 2a=3b
Đến đó bạn tự thay vào mà làm nha
Tk mk nha
GPT:
1, \(6x^2+10x-92+\sqrt{\left(x+70\right)\left(2x^2+4x+16\right)}=0\)
2,\(x+3+\sqrt{1-x^2}=3\sqrt{x+1}+\sqrt{1-x}\)
\(\left(1\right)\sqrt{x^2-9}-2\sqrt{x-3}=0\)
\(\left(2\right)\sqrt{4x+1}-\sqrt{3x-4}=1\)
\(\left(3\right)\sqrt{x^2-10x+25}=5-x\)
\(\left(4\right)\sqrt{x^2-8x+16}=x+2\)
Giải Pt: \(\left(4x+1\right)\sqrt{x^2+1}=2x^2-2x+2\)
giải pt
\(\sqrt{4x^2}=3\)
\(\sqrt{x^2-6x+9}=2\)
\(\sqrt{\left(2x-3\right)^2}=6\)
\(\sqrt{25x^2}=100\)
gpt:\(\sqrt{3x^2+6x+4}+\sqrt{2x^2+4x+11}=\left(1-x\right)\left(x+3\right)\)
\(\sqrt{3x^2+6x+7}+\sqrt{5x^2+10x+21}=5-x^2-2x\)
\(\sqrt{x^2-x+2}+\sqrt{x^2-3x+6}=2x\)
\(a,3x^3+6x^2-4x=0\)
\(b,\left(x+1\right)^3-x+1=\left(x-1\right)\left(x-2\right)\)
\(c,\left(x^2+x+1\right)^2=\left(4x-1\right)^2\)
\(d,\left(2x^2+3\right)^2-10x^3-15x=0\)
a) x+\(\sqrt{\left(x-2\right)^2}\)
b) \(\sqrt{\left(x-3\right)^2}\) -x
c) x-\(\sqrt{\left(x-1\right)^2}\)
d) \(\sqrt{m^2-6m+9}\) -2m
e) m-\(\sqrt{m^2-2m+1}\)
f) 2x-\(\sqrt{4x^2+4x+1}\)
g)\(\sqrt{x^2-10x+25}\) -x
h) \(\dfrac{\sqrt{x^2+10x+25}}{x^2-25}\)
i) \(\dfrac{\sqrt{1-2m+m^2}}{m^2-1}\)
\(6x^2-10x+5-\left(4x-1\right)\sqrt{6x^2-6x+5}=0\)
Tất cả đều có điều kiện \(x\ge0\)
a,\(\sqrt{x^2-6x+9}+x=11\)
b,\(\sqrt{3x^2-4x+3=1-2x}\)
c,\(\sqrt{16\left(x+1\right)}-\sqrt{9\left(x+1\right)}=4\)
d,\(\sqrt{9x+9}+\sqrt{4x+4}=\sqrt{x+1}\)
