a.Vo nghiem
b.\(DK:x\ge0\)
\(\frac{\sqrt{x}-1}{\sqrt{x}+3}=\frac{\sqrt{x}-2}{\sqrt{x}+1}\)
\(\Leftrightarrow\frac{\left(\sqrt{x}-1\right)\left(\sqrt{x}+1\right)-\left(\sqrt{x}-2\right)\left(\sqrt{x}+3\right)}{\left(\sqrt{x}+3\right)\left(\sqrt{x}+1\right)}=0\)
\(\Rightarrow x-1-x+\sqrt{x}+6=0\)
\(\Leftrightarrow x=5\left(n\right)\)