a,\(2x-5=3x+15\)
\(3x-2x=-5-15\)
\(x=-20\)
b,\(\frac{2}{x-1}=\frac{6}{x+1}\)
\(2x+2=6x-6\)
\(4x=8\)
\(x=2\)
\(\frac{2x+1}{x-1}=\frac{5.\left(x-1\right)}{x+1}\)
\(\frac{2x+1}{x-1}=\frac{5x-5}{x+1}\)
\(2x^2+3x+1=5x^2-10+5\)
\(3x^2-3x=10-5+1=6\)
\(3x.\left(x-1\right)=6\)
\(x.\left(x-1\right)=3\)
Lập bảng
\(\frac{2x+1}{x-1}=\frac{5.\left(x-1\right)}{x+1}\)
\(\Leftrightarrow\left(2x+1\right).\left(x+1\right)=5.\left(x-1\right)^2\)
\(\Leftrightarrow2x^2+3x+1=5x^2-2x+1\)
\(\Leftrightarrow-3x^2+5x=0\)
\(\Leftrightarrow x.\left(-3x+5\right)=0\)
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p/s: đề k cho nguyên cứ "lập bảng" như thật :VVV vl
\(\frac{x}{x-1}-\frac{2x}{x^2-1}=0\)
\(\frac{x}{x-1}-\frac{2}{x-1}=0\)
\(\frac{x-2}{x-1}=0\Rightarrow x-2=0\Rightarrow x=2\)
Ukm c ơn quên là nó k cho cơn :V
e,\(\frac{1}{x-2}+3=\frac{x-3}{2-x}\)
\(\frac{3x-5}{x-2}=\frac{x-3}{2-x}\)
\(\left(-3\right)x^2+11x+10=x^2-5x+6\)
\(4x^2-16x=-16\)
\(4x.\left(x-4\right)=-16\)
\(x.\left(x-4\right)=-4\)
...