Question

giải phương trình

Answer 1

Answer 2

Answer 3

c: =>|5x-3|=x-1

\(\Leftrightarrow\left\{{}\begin{matrix}x>=1\\\left(5x-3-x+1\right)\left(5x-3+x-1\right)=0\end{matrix}\right.\)

\(\Leftrightarrow\left\{{}\begin{matrix}x>=1\\\left(4x-2\right)\left(6x-4\right)=0\end{matrix}\right.\Leftrightarrow x\in\varnothing\)

d: =>\(\left\{{}\begin{matrix}x^2-x-2=x+1\\x>=-1\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x^2-2x-3=0\\x>=-1\end{matrix}\right.\)

=>x=3 hoặc x=-1

Answer 4

Answer 5

Answer 6

this is C

Answer 7

Answer 8

Answer 9

this is D