Question

giải phương trình sau

\(\dfrac{x+5}{4}-\dfrac{2x-3}{3}=\dfrac{6x-1}{8}+\dfrac{2x-1}{12}\)

Answer 1

\(\dfrac{x+5}{4}-\dfrac{2x-3}{3}=\dfrac{6x-1}{8}+\dfrac{2x-1}{12}\)

\(\Leftrightarrow\dfrac{6\left(x+5\right)-8\left(2x-3\right)}{24}=\dfrac{3\left(6x-1\right)+2\left(2x-1\right)}{24}\)

\(\Leftrightarrow6\left(x+5\right)-8\left(2x-3\right)=3\left(6x-1\right)+2\left(2x-1\right)\)

\(\Leftrightarrow6x+30-16x+24=18x-3+4x-2\)

\(\Leftrightarrow-32x=-59\)

\(\Leftrightarrow x=\dfrac{59}{32}\)

Vậy \(S=\left\{\dfrac{59}{32}\right\}\)