Question

giải phương trình sau

3(x-1)(2x-1)= 5(x+8)(x-1)

Answer 1

\(3\left(x-1\right)\left(2x-1\right)=5\left(x+8\right)\left(x-1\right)\)

\(\Rightarrow3\left(x-1\right)\left(2x-1\right)-5\left(x+8\right)\left(x-1\right)=0\)

\(\text{⇒(x-1)}\left[3\left(2x-1\right)-5\left(x+8\right)\right]=0\)

\(\text{⇒(x-1)}\left[6x-3-5x-40\right]=0\)

\(\text{⇒(x-1)}\left(x-43\right)=0\)

\(\Rightarrow\left[{}\begin{matrix}x-1=0\\x-43=0\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=1\\x=43\end{matrix}\right.\)