Question

Giải Phương trình căn2x=4

Answer 1

\(\sqrt{2x}=4\)

\(\Leftrightarrow2x=4^2\) (ĐK: \(x\ge0\))

\(\Leftrightarrow2x=16\)

\(\Leftrightarrow x=\dfrac{16}{2}\)

\(\Leftrightarrow x=8\left(tm\right)\)

Vậy \(x=8\)

Answer 2

    \(\sqrt{x}\) = 4
↔(\(\sqrt{x}\))\(^2\) = 4\(^2\)
↔ x = 16