\(3x+2\left(1-2x\right)=5x+1\\ \Leftrightarrow3x+2-4x-5x-1=0\\ \Leftrightarrow-6x+1=0\\ \Leftrightarrow-6x=-1\\ \Leftrightarrow x=\dfrac{1}{6}\)
Vậy pt có tập nghiệm \(S=\left\{\dfrac{1}{6}\right\}\)
\(3x+2\left(1-2x\right)=5x+1\)
\(\Leftrightarrow3x+2-4x=5x+1\)
\(\Leftrightarrow-x-5x=-2+1\)
\(\Leftrightarrow-4x=-1\)
\(\Leftrightarrow x=\dfrac{1}{4}\)