Question

Giải hộ mình bài 9 với ạ

Answer 1

a) Zn + 2HCl --> ZnCl₂ + H₂

b) \(n_{Zn}=\dfrac{6,5}{65}=0,1\left(mol\right)\)

PTHH: Zn + 2HCl --> ZnCl₂ + H₂

_____0,1-->0,2---------------->0,1

=> V_H2 = 0,1.22,4 = 2,24(l)

c) m_HCl = 36,5.0,2 = 7,3(g)

Answer 2

\(a/PTHH:Zn+2HCl-> ZnCl_{2}+H_{2} nZn=\dfrac{6,5}{65} =0,1 (mol) b/V_{H_{2}}=0,1.22,4=2,24(l) \)

Answer 3

\(a/PTHH:Zn+2HCl-> ZnCl_{2}+H_{2} nZn=\dfrac{6,5}{65} =0,1 (mol) b/V_{H_{2}}=0,1.22,4=2,24(l) \)

Answer 4

\(a/PTHH:Zn+2HCl-> ZnCl_{2}+H_{2} nZn=\dfrac{6,5}{65} =0,1 (mol) b/V_{H_{2}}=0,1.22,4=2,24(l) \)