Lời giải:
\(\frac{2019\times 2022-19}{2020\times 2021-21}=\frac{(2020-1)\times 2022-19}{2020\times 2021-21}=\frac{2020\times 2022-2022-19}{2020\times 2021-21}\)
\(=\frac{2020\times (2021+1)-2022-19}{2020\times 2021-21}=\frac{2021\times 2021+2020-2022-19}{2020\times 2021-21}=\frac{2020\times 2021-21}{2020\times 2021-21}=1\)
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