\(\left\{{}\begin{matrix}2x+\dfrac{1}{4}-y-\dfrac{2}{3}=\dfrac{1}{12}\\x+\dfrac{5}{2}-y+\dfrac{7}{3}=-4\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}2x-y=\dfrac{1}{12}-\dfrac{1}{4}+\dfrac{2}{3}\\x-y=-4-\dfrac{5}{2}-\dfrac{7}{3}\end{matrix}\right.\\ \Leftrightarrow\left\{{}\begin{matrix}2x-y=\dfrac{1}{12}-\dfrac{3}{12}+\dfrac{8}{12}=\dfrac{1}{2}\\x-y=\dfrac{-24}{6}+\dfrac{-15}{6}+\dfrac{-14}{6}=\dfrac{-53}{6}\end{matrix}\right.\\ \Leftrightarrow\left\{{}\begin{matrix}x=\dfrac{1}{2}-\left(-\dfrac{53}{6}\right)=\dfrac{56}{6}=\dfrac{28}{3}\\x-y=-\dfrac{53}{6}\end{matrix}\right.\\ \Leftrightarrow\left\{{}\begin{matrix}x=\dfrac{28}{3}\\y=x+\dfrac{53}{6}=\dfrac{28}{3}+\dfrac{53}{6}=\dfrac{109}{6}\end{matrix}\right.\)
