h: \(6\dfrac{3}{10}-\left(3\dfrac{4}{7}+2\dfrac{3}{10}\right)\)
\(=6+\dfrac{3}{10}-3-\dfrac{4}{7}-2-\dfrac{3}{10}\)
\(=1-\dfrac{4}{7}=\dfrac{3}{7}\)
i: \(\left(7\dfrac{4}{9}+4\dfrac{7}{11}\right)-3\dfrac{4}{9}\)
\(=7+\dfrac{4}{9}+4+\dfrac{7}{11}-3-\dfrac{4}{9}\)
\(=8+\dfrac{7}{11}=\dfrac{95}{11}\)