Question

giai chi tiet nhe

 

Answer 1

a: ĐKXĐ: x<>2; x<>-3

b: \(=\dfrac{x^2-4-5-x-3}{\left(x-2\right)\left(x+3\right)}=\dfrac{\left(x-4\right)\left(x+3\right)}{\left(x-2\right)\left(x+3\right)}=\dfrac{x-4}{x-2}\)

c: Để \(A=\dfrac{-3}{4}\) thì \(\dfrac{x-4}{x-2}=\dfrac{-3}{4}\)

=>4x-16=-3x+6

=>7x=22

=>x=22/7

d: Để A nguyên thì x-2-2 chia hết cho x-2

=>\(x-2\in\left\{1;-1;2;-2\right\}\)

=>\(x\in\left\{3;1;4;0\right\}\)

e: x^2-9=0

=>x=-3(loại) hoặc x=3(nhận)

Khi x=3 thì \(A=\dfrac{3-4}{3-2}=-1\)