Question

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Answer 1

a: \(=\dfrac{2}{7}\cdot\dfrac{-3}{4}\cdot\dfrac{4}{7}=\dfrac{-6}{49}\)

b: \(=\dfrac{3}{5}:\dfrac{1}{15}=\dfrac{3}{5}\cdot15=9\)

c: \(=\dfrac{41}{7}-3-\dfrac{1}{2}=\dfrac{33}{14}\)

d: \(=-\dfrac{25}{12}-\dfrac{23}{12}-\dfrac{3}{2}=-4-\dfrac{3}{2}=-\dfrac{11}{2}\)

Answer 2

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