Question

giải các phương trình sau:

a) (5x + 2)(2x - 6) = 0

a) (5x + 2)(2x - 6) = 0
b) (5x)/(2x + 2) + 1 = 8/(x + 1)
(mik cần gấp ạ, được ít cũng được ạ)

 

Answer 1

a)\(\left(5x+2\right)\left(2x-6\right)=0\\ \left\{{}\begin{matrix}5x+2=0\Leftrightarrow5x=-2\Leftrightarrow x=\dfrac{-2}{5}\\2x-6=0\Leftrightarrow2x=6\Leftrightarrow x=\dfrac{6}{2}=3\end{matrix}\right.\)

b)\(\dfrac{5x}{2x+2}+1=\dfrac{8}{x+1}\\ \Leftrightarrow\dfrac{5x}{2\left(x+1\right)}+1=\dfrac{8}{x+1}\\ \Leftrightarrow\dfrac{5x+2\left(x+1\right)}{2\left(x+1\right)}=\dfrac{2\cdot8}{2\left(x+1\right)}\\ \Leftrightarrow5x+2\left(x+1\right)=16\\ \Leftrightarrow5x+2x+2=16\\ \Leftrightarrow5x+2x=16-2\\ \Leftrightarrow7x=14\\ \Leftrightarrow x=\dfrac{14}{7}=2\)

Answer 2

a, <=>5x+2=0<=>x=-2/5
    <=>2x-6=0<=>x=6/2=3
mik có tí việc ko lm hết cho bn đc xl