=>(3x-4)^5-(3x-4)^7=0
=>(3x-4)^5-(3x-4)^5.(3x-4)^2=0
=>(3x-4)^5.[1-(3x-4)^2]=0
=>(3x-4)^5=0=>3x-4=0=>3x=4=>x=4/3
hoặc 1-(3x-4)^2=0=>(3x-4)^2=1=>3x-4=1 hoặc 3x-4=-1
=>x=5/3 hoặc x=1
mà x nguyên nên x=1
=>(3x-4)^5-(3x-4)^7=0
=>(3x-4)^5-(3x-4)^5.(3x-4)^2=0
=>(3x-4)^5.[1-(3x-4)^2]=0
=>(3x-4)^5=0=>3x-4=0=>3x=4=>x=4/3
hoặc 1-(3x-4)^2=0=>(3x-4)^2=1=>3x-4=1 hoặc 3x-4=-1
=>x=5/3 hoặc x=1
mà x nguyên nên x=1
Tap hop cac gia tri nguyen cua x thoa man 3x-4=x+2
tap hop cac gia tri nguyen cua x thoa man |3x -4|=|x+2|
1. so x>0 thoa man \(\frac{5}{x}=\frac{x+1}{22}\)
2. GTLN cua x thoa man \(5^{\left(x-2\right)\left(x+3\right)}\)
3. Gia tri x<0 thoa man /\(x^2+50\)/=/\(-2x^2\)-1/
4. Gia tri nguyen cua x thoa man \(\left(3x-4\right)^5\)=\(^{\left(3x-4\right)^7}\)la x=
5. So gia tri cua x thoa man /x-2014/+/x-2015/=0
6. Gia tri cua x de bieu thuc A=\(\frac{x-3+5}{3-x+2}\)dat gia tri lon nhat la x=
tap hop cac gia tri nguyen x thoa man |3x-4|=|x+2|
gia tri cua x > 0 thoa man : (3x -2)4 = 390625
c1: Tap hop cac gia tri nguyen cua x thoa man \(\left(x+\frac{5}{4}\right)\left(x-\frac{19}{7}\right)\)<0
c2: Neu x,y la cac so nguyen thoa man 2xy+4y=6 thi y co the nhan nhung gia tri nam trong tap hop nao
c3: tim 3 so x,y,z biet x+y=8,x+z=10,y+z=12
C4: Gia tri cua x thoa man (x+3)^2=25 va x^3>0 la x=
1/tong cac gia tri nguyen cua x thoa man /x-0,2/<13
2/ti so gia A va B biet 2/7 cua A gap 4/9 lan 3/10 cua B
Gia tri cua x thoa man 2x+2/3x-6=2x-6/3x-15
tap hop cac gia tri nguyen cua x thoa man (x^2+4x+13) chia het cho x+4 co so phan tu la