\(\frac{3x+2}{5x+7}=\frac{3x-1}{5x+1}\)ĐKXĐ: \(x\ne-\frac{1}{5};x\ne-\frac{7}{5}\)
\(\Rightarrow\left(3x+2\right)\left(5x+1\right)=\left(5x+7\right)\left(3x-1\right)\)
\(\Leftrightarrow15x^2+13x+2=15x^2+16x-7\)
\(\Leftrightarrow3x=9\)
\(\Leftrightarrow x=3\)
\(\frac{3x+2}{5x+7}\)= \(\frac{3x-1}{5x+1}ĐKXĐ:x#\)- \(\frac{1}{5};x#-\frac{1}{5};x#-\frac{7}{5}\)
< = > (\(\left(3x+2\right)\left(5x+1\right)=\left(5x+7\right)\left(3x-1\right)\)
< = > \(3x=9\)
\(x=3\)
số phải tìm :3
Toán lớp 7
lê thị thu huyền 07/07/2017 lúc 15:44
Thống kê hỏi đáp
Báo cáo sai phạm
3x+25x+7 =3x−15x+1 ĐKXĐ: x≠−15 ;x≠−75
⇒(3x+2)(5x+1)=(5x+7)(3x−1)
⇔15x2+13x+2=15x2+16x−7
⇔3x=9
hok tốt !
