\(\left(1+3+...+99\right).x=2+4+...+100\)
\(\dfrac{\left(99+1\right).\left[\left(99-1\right):2+1\right]}{2}.x=\dfrac{\left(100+2\right).\left[\left(100-2\right):2+1\right]}{2}\)
\(2500.x=2550\)
\(x=\dfrac{2550}{2500}=\dfrac{51}{50}\)
Đúng 1
Bình luận (0)