Question

Gấppp

Answer 1

\(a,\Leftrightarrow x\left(x-3\right)-2\left(x-3\right)=0\\ \Leftrightarrow\left(x-2\right)\left(x-3\right)=0\Leftrightarrow\left[{}\begin{matrix}x=2\\x=3\end{matrix}\right.\\ b,\Leftrightarrow\left(2x-5\right)\left(2x+5\right)+\left(2x+5\right)^2=0\\ \Leftrightarrow\left(2x+5\right)\left(2x-5+2x+5\right)=0\\ \Leftrightarrow4x\left(2x+5\right)=0\Leftrightarrow\left[{}\begin{matrix}x=0\\x=-\dfrac{5}{2}\end{matrix}\right.\)