\(a,\Leftrightarrow\left(x-3\right)\left(5x-1\right)=0\Leftrightarrow\left[{}\begin{matrix}x=3\\x=\dfrac{1}{5}\end{matrix}\right.\\ b,\Leftrightarrow x\left(x+1-x+3\right)=0\\ \Leftrightarrow4x=0\Leftrightarrow x=0\\ c,\Leftrightarrow2\left(x^2+x+\dfrac{1}{4}\right)=0\\ \Leftrightarrow2\left(x+\dfrac{1}{2}\right)^2=0\\ \Leftrightarrow x+\dfrac{1}{2}=0\Leftrightarrow x=-\dfrac{1}{2}\)
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