Question

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Answer 1

Đặt \(\left\{{}\begin{matrix}n_{Na}=2x\left(mol\right)\\n_{Al}=x\left(mol\right)\\n_{Fe}=y\left(mol\right)\end{matrix}\right.\)

PTHH: 2Na + 2H₂O --> 2NaOH + H₂

              2x--------------->2x------>x

             2NaOH + 2Al + 2H₂O --> 2NaAlO₂ + 3H₂

                   x<------x-------------------------->1,5x

=> Y là Fe

n_khí(TN1) = 2,5x (mol)

PTHH: Fe + H₂SO₄ --> FeSO₄ + H₂

             y-------------------------->y

=> n_khí(TN2) = y (mol)

=> 2,5x.0,25 = y

=> \(\dfrac{y}{x}=\dfrac{5}{8}\)