Question

G= (x + a)(x + 2a)(x + 3a)(x + 4a) + a⁴

E = (3x + 2)(3x – 5)(x – 1)(9x + 10) + 24x²
F = 4(x² + 15x + 50)(x² + 18x + 72) – 3x²

D = (3x² – x - 2)(27x² – 15x – 50) + 24x²

  ^{Các bn giúp mk nha, mk đg cần gấp, tksss}

 

Answer 1

e) Ta có: \(E=\left(3x+2\right)\left(3x-5\right)\left(x-1\right)\left(9x+10\right)+24x^2\)

\(=\left(9x^2-15x+6x-10\right)\left(9x^2+10x-9x-10\right)+24x^2\)

\(=\left(9x^2-10-9x\right)\left(9x^2-10+x\right)+24x^2\)

\(=\left(9x^2-10\right)^2-8x\left(9x^2-10\right)-9x^2+24x^2\)

\(=\left(9x^2-10\right)^2-8x\left(9x^2-10\right)+15x^2\)

\(=\left(9x^2-10\right)^2-3x\left(9x^2-10\right)-5x\left(9x^2-10\right)+15x^2\)

\(=\left(9x^2-10\right)\left(9x^2-3x-10\right)-5x\left(9x^2-10-3x\right)\)

\(=\left(9x^2-3x-10\right)\left(9x^2-5x-10\right)\)